4(b-2)-10=29(b+3)

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Solution for 4(b-2)-10=29(b+3) equation: 



4(b-2)-10=29(b+3)

We move all terms to the left:

4(b-2)-10-(29(b+3))=0

We multiply parentheses

4b-(29(b+3))-8-10=0



We calculate terms in parentheses: -(29(b+3)), so:

29(b+3)

We multiply parentheses

29b+87

Back to the equation:

-(29b+87)



We add all the numbers together, and all the variables

4b-(29b+87)-18=0

We get rid of parentheses

4b-29b-87-18=0

We add all the numbers together, and all the variables

-25b-105=0

We move all terms containing b to the left, all other terms to the right

-25b=105

b=105/-25

b=-4+1/5

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