(6-4)x(x-3)=2x

Solution for (6-4)x(x-3)=2x equation:

(6-4)x(x-3)=2x

We move all terms to the left:

(6-4)x(x-3)-(2x)=0

We add all the numbers together, and all the variables

2x(x-3)-2x=0

We add all the numbers together, and all the variables

-2x+2x(x-3)=0

We multiply parentheses

2x^2-2x-6x=0

We add all the numbers together, and all the variables

2x^2-8x=0

a = 2; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·2·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*2}=\frac{16}{4}
=4
$