4(b-2)-(-8b+8)=80

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Solution for 4(b-2)-(-8b+8)=80 equation: 



4(b-2)-(-8b+8)=80

We move all terms to the left:

4(b-2)-(-8b+8)-(80)=0

We multiply parentheses

4b-(-8b+8)-8-80=0

We get rid of parentheses

4b+8b-8-8-80=0

We add all the numbers together, and all the variables

12b-96=0

We move all terms containing b to the left, all other terms to the right

12b=96

b=96/12

b=8

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