110=5(-3b-1)-5

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Solution for 110=5(-3b-1)-5 equation: 



110=5(-3b-1)-5

We move all terms to the left:

110-(5(-3b-1)-5)=0



We calculate terms in parentheses: -(5(-3b-1)-5), so:

5(-3b-1)-5

We multiply parentheses

-15b-5-5

We add all the numbers together, and all the variables

-15b-10

Back to the equation:

-(-15b-10)



We get rid of parentheses

15b+10+110=0

We add all the numbers together, and all the variables

15b+120=0

We move all terms containing b to the left, all other terms to the right

15b=-120

b=-120/15

b=-8

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