4(b-1)=7(b-2)

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Solution for 4(b-1)=7(b-2) equation: 



4(b-1)=7(b-2)

We move all terms to the left:

4(b-1)-(7(b-2))=0

We multiply parentheses

4b-(7(b-2))-4=0



We calculate terms in parentheses: -(7(b-2)), so:

7(b-2)

We multiply parentheses

7b-14

Back to the equation:

-(7b-14)



We get rid of parentheses

4b-7b+14-4=0

We add all the numbers together, and all the variables

-3b+10=0

We move all terms containing b to the left, all other terms to the right

-3b=-10

b=-10/-3

b=3+1/3

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