(x+3x)(x-1)=437

Solution for (x+3x)(x-1)=437 equation:

(x+3x)(x-1)=437

We move all terms to the left:

(x+3x)(x-1)-(437)=0

We add all the numbers together, and all the variables

(+4x)(x-1)-437=0

We multiply parentheses ..

(+4x^2-4x)-437=0

We get rid of parentheses

4x^2-4x-437=0

a = 4; b = -4; c = -437;
Δ = b2-4ac
Δ = -42-4·4·(-437)
Δ = 7008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7008}=\sqrt{16*438}=\sqrt{16}*\sqrt{438}=4\sqrt{438}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{438}}{2*4}=\frac{4-4\sqrt{438}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{438}}{2*4}=\frac{4+4\sqrt{438}}{8}
$