4(b-1)+3(b+2)=5(b-4)

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Solution for 4(b-1)+3(b+2)=5(b-4) equation: 



4(b-1)+3(b+2)=5(b-4)

We move all terms to the left:

4(b-1)+3(b+2)-(5(b-4))=0

We multiply parentheses

4b+3b-(5(b-4))-4+6=0



We calculate terms in parentheses: -(5(b-4)), so:

5(b-4)

We multiply parentheses

5b-20

Back to the equation:

-(5b-20)



We add all the numbers together, and all the variables

7b-(5b-20)+2=0

We get rid of parentheses

7b-5b+20+2=0

We add all the numbers together, and all the variables

2b+22=0

We move all terms containing b to the left, all other terms to the right

2b=-22

b=-22/2

b=-11

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