2y+2(y+3)=20

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Solution for 2y+2(y+3)=20 equation: 



2y+2(y+3)=20

We move all terms to the left:

2y+2(y+3)-(20)=0

We multiply parentheses

2y+2y+6-20=0

We add all the numbers together, and all the variables

4y-14=0

We move all terms containing y to the left, all other terms to the right

4y=14

y=14/4

y=3+1/2

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