4(b+2)+4=12+4b

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Solution for 4(b+2)+4=12+4b equation: 



4(b+2)+4=12+4b

We move all terms to the left:

4(b+2)+4-(12+4b)=0

We add all the numbers together, and all the variables

4(b+2)-(4b+12)+4=0

We multiply parentheses

4b-(4b+12)+8+4=0

We get rid of parentheses

4b-4b-12+8+4=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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