(3k+2)/2=2k=2

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Solution for (3k+2)/2=2k=2 equation: 



(3k+2)/2=2k=2

We move all terms to the left:

(3k+2)/2-(2k)=0

We add all the numbers together, and all the variables

-2k+(3k+2)/2=0

We multiply all the terms by the denominator


-2k*2+(3k+2)=0

Wy multiply elements

-4k+(3k+2)=0

We get rid of parentheses

-4k+3k+2=0

We add all the numbers together, and all the variables

-1k+2=0

We move all terms containing k to the left, all other terms to the right

-k=-2

k=-2/-1

k=+2

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