4(a-6)+12=7(a+4)-5a

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Solution for 4(a-6)+12=7(a+4)-5a equation: 



4(a-6)+12=7(a+4)-5a

We move all terms to the left:

4(a-6)+12-(7(a+4)-5a)=0

We multiply parentheses

4a-(7(a+4)-5a)-24+12=0



We calculate terms in parentheses: -(7(a+4)-5a), so:

7(a+4)-5a

We add all the numbers together, and all the variables

-5a+7(a+4)

We multiply parentheses

-5a+7a+28

We add all the numbers together, and all the variables

2a+28

Back to the equation:

-(2a+28)



We add all the numbers together, and all the variables

4a-(2a+28)-12=0

We get rid of parentheses

4a-2a-28-12=0

We add all the numbers together, and all the variables

2a-40=0

We move all terms containing a to the left, all other terms to the right

2a=40

a=40/2

a=20

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