12v-3(3v-6)=-2(-3v+4)+41

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Solution for 12v-3(3v-6)=-2(-3v+4)+41 equation: 



12v-3(3v-6)=-2(-3v+4)+41

We move all terms to the left:

12v-3(3v-6)-(-2(-3v+4)+41)=0

We multiply parentheses

12v-9v-(-2(-3v+4)+41)+18=0



We calculate terms in parentheses: -(-2(-3v+4)+41), so:

-2(-3v+4)+41

We multiply parentheses

6v-8+41

We add all the numbers together, and all the variables

6v+33

Back to the equation:

-(6v+33)



We add all the numbers together, and all the variables

3v-(6v+33)+18=0

We get rid of parentheses

3v-6v-33+18=0

We add all the numbers together, and all the variables

-3v-15=0

We move all terms containing v to the left, all other terms to the right

-3v=15

v=15/-3

v=-5

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