4(a-3)=10(2a+4)

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Solution for 4(a-3)=10(2a+4) equation: 



4(a-3)=10(2a+4)

We move all terms to the left:

4(a-3)-(10(2a+4))=0

We multiply parentheses

4a-(10(2a+4))-12=0



We calculate terms in parentheses: -(10(2a+4)), so:

10(2a+4)

We multiply parentheses

20a+40

Back to the equation:

-(20a+40)



We get rid of parentheses

4a-20a-40-12=0

We add all the numbers together, and all the variables

-16a-52=0

We move all terms containing a to the left, all other terms to the right

-16a=52

a=52/-16

a=-3+1/4

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