4(a+3)-2=3(3a-4)-3

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Solution for 4(a+3)-2=3(3a-4)-3 equation: 



4(a+3)-2=3(3a-4)-3

We move all terms to the left:

4(a+3)-2-(3(3a-4)-3)=0

We multiply parentheses

4a-(3(3a-4)-3)+12-2=0



We calculate terms in parentheses: -(3(3a-4)-3), so:

3(3a-4)-3

We multiply parentheses

9a-12-3

We add all the numbers together, and all the variables

9a-15

Back to the equation:

-(9a-15)



We add all the numbers together, and all the variables

4a-(9a-15)+10=0

We get rid of parentheses

4a-9a+15+10=0

We add all the numbers together, and all the variables

-5a+25=0

We move all terms containing a to the left, all other terms to the right

-5a=-25

a=-25/-5

a=+5

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