-3(y-5)+10=3y+20

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Solution for -3(y-5)+10=3y+20 equation: 



-3(y-5)+10=3y+20

We move all terms to the left:

-3(y-5)+10-(3y+20)=0

We multiply parentheses

-3y-(3y+20)+15+10=0

We get rid of parentheses

-3y-3y-20+15+10=0

We add all the numbers together, and all the variables

-6y+5=0

We move all terms containing y to the left, all other terms to the right

-6y=-5

y=-5/-6

y=5/6

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