4(a+3)+2(a+6)=48

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Solution for 4(a+3)+2(a+6)=48 equation: 



4(a+3)+2(a+6)=48

We move all terms to the left:

4(a+3)+2(a+6)-(48)=0

We multiply parentheses

4a+2a+12+12-48=0

We add all the numbers together, and all the variables

6a-24=0

We move all terms containing a to the left, all other terms to the right

6a=24

a=24/6

a=4

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