6(t-3)+1=3+-2(7-t)

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Solution for 6(t-3)+1=3+-2(7-t) equation: 



6(t-3)+1=3+-2(7-t)

We move all terms to the left:

6(t-3)+1-(3+-2(7-t))=0

We add all the numbers together, and all the variables

6(t-3)-(3+-2(-1t+7))+1=0

We use the square of the difference formula

6(t-3)-(3-2(-1t+7))+1=0

We multiply parentheses

6t-(3-2(-1t+7))-18+1=0



We calculate terms in parentheses: -(3-2(-1t+7)), so:

3-2(-1t+7)

determiningTheFunctionDomain
-2(-1t+7)+3

We multiply parentheses

2t-14+3

We add all the numbers together, and all the variables

2t-11

Back to the equation:

-(2t-11)



We add all the numbers together, and all the variables

6t-(2t-11)-17=0

We get rid of parentheses

6t-2t+11-17=0

We add all the numbers together, and all the variables

4t-6=0

We move all terms containing t to the left, all other terms to the right

4t=6

t=6/4

t=1+1/2

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