4(a+2)-5(a+1)=a-1

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Solution for 4(a+2)-5(a+1)=a-1 equation: 



4(a+2)-5(a+1)=a-1

We move all terms to the left:

4(a+2)-5(a+1)-(a-1)=0

We multiply parentheses

4a-5a-(a-1)+8-5=0

We get rid of parentheses

4a-5a-a+1+8-5=0

We add all the numbers together, and all the variables

-2a+4=0

We move all terms containing a to the left, all other terms to the right

-2a=-4

a=-4/-2

a=+2

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