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9x(2)+11x+2=0
We add all the numbers together, and all the variables
9x^2+11x+2=0
a = 9; b = 11; c = +2;
Δ = b2-4ac
Δ = 112-4·9·2
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-7}{2*9}=\frac{-18}{18} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+7}{2*9}=\frac{-4}{18} =-2/9 $
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