4(9x-5)+40=10(3x-+17)

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Solution for 4(9x-5)+40=10(3x-+17) equation: 



4(9x-5)+40=10(3x-+17)

We move all terms to the left:

4(9x-5)+40-(10(3x-+17))=0

We add all the numbers together, and all the variables

4(9x-5)-(10(+3x))+40=0

We multiply parentheses

36x-(10(+3x))-20+40=0



We calculate terms in parentheses: -(10(+3x)), so:

10(+3x)

We multiply parentheses

30x

Back to the equation:

-(30x)



We add all the numbers together, and all the variables

6x+20=0

We move all terms containing x to the left, all other terms to the right

6x=-20

x=-20/6

x=-3+1/3

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