4(9x-5)+40=10(3x-+17

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Solution for 4(9x-5)+40=10(3x-+17 equation: 



4(9x-5)+40=10(3x-+17

We move all terms to the left:

4(9x-5)+40-(10(3x-+17)=0

We add all the numbers together, and all the variables

4(9x-5)-(10(+3x)+40=0

We multiply parentheses

36x-(10(+3x)+40-20=0

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