4(8-3x)=32+8(-x-2)

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Solution for 4(8-3x)=32+8(-x-2) equation: 



4(8-3x)=32+8(-x-2)

We move all terms to the left:

4(8-3x)-(32+8(-x-2))=0

We add all the numbers together, and all the variables

4(-3x+8)-(32+8(-1x-2))=0

We multiply parentheses

-12x-(32+8(-1x-2))+32=0



We calculate terms in parentheses: -(32+8(-1x-2)), so:

32+8(-1x-2)

determiningTheFunctionDomain
8(-1x-2)+32

We multiply parentheses

-8x-16+32

We add all the numbers together, and all the variables

-8x+16

Back to the equation:

-(-8x+16)



We get rid of parentheses

-12x+8x-16+32=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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