3y*y=560

Solution for 3y*y=560 equation:

3y*y=560

We move all terms to the left:

3y*y-(560)=0

Wy multiply elements

3y^2-560=0

a = 3; b = 0; c = -560;
Δ = b2-4ac
Δ = 02-4·3·(-560)
Δ = 6720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6720}=\sqrt{64*105}=\sqrt{64}*\sqrt{105}=8\sqrt{105}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{105}}{2*3}=\frac{0-8\sqrt{105}}{6}
=-\frac{8\sqrt{105}}{6}
=-\frac{4\sqrt{105}}{3}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{105}}{2*3}=\frac{0+8\sqrt{105}}{6}
=\frac{8\sqrt{105}}{6}
=\frac{4\sqrt{105}}{3}
$