3(k-5)=-2(3k+6)

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Solution for 3(k-5)=-2(3k+6) equation: 



3(k-5)=-2(3k+6)

We move all terms to the left:

3(k-5)-(-2(3k+6))=0

We multiply parentheses

3k-(-2(3k+6))-15=0



We calculate terms in parentheses: -(-2(3k+6)), so:

-2(3k+6)

We multiply parentheses

-6k-12

Back to the equation:

-(-6k-12)



We get rid of parentheses

3k+6k+12-15=0

We add all the numbers together, and all the variables

9k-3=0

We move all terms containing k to the left, all other terms to the right

9k=3

k=3/9

k=1/3

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