4(8+8c)=4(8-3c)

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Solution for 4(8+8c)=4(8-3c) equation: 



4(8+8c)=4(8-3c)

We move all terms to the left:

4(8+8c)-(4(8-3c))=0

We add all the numbers together, and all the variables

4(8c+8)-(4(-3c+8))=0

We multiply parentheses

32c-(4(-3c+8))+32=0



We calculate terms in parentheses: -(4(-3c+8)), so:

4(-3c+8)

We multiply parentheses

-12c+32

Back to the equation:

-(-12c+32)



We get rid of parentheses

32c+12c-32+32=0

We add all the numbers together, and all the variables

44c=0

c=0/44

c=0

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