4(7z-9)-7(4z+3)=6(69z-10)

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Solution for 4(7z-9)-7(4z+3)=6(69z-10) equation: 



4(7z-9)-7(4z+3)=6(69z-10)

We move all terms to the left:

4(7z-9)-7(4z+3)-(6(69z-10))=0

We multiply parentheses

28z-28z-(6(69z-10))-36-21=0



We calculate terms in parentheses: -(6(69z-10)), so:

6(69z-10)

We multiply parentheses

414z-60

Back to the equation:

-(414z-60)



We add all the numbers together, and all the variables

-(414z-60)-57=0

We get rid of parentheses

-414z+60-57=0

We add all the numbers together, and all the variables

-414z+3=0

We move all terms containing z to the left, all other terms to the right

-414z=-3

z=-3/-414

z=1/138

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