3(x+2)=2(x-10)

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Solution for 3(x+2)=2(x-10) equation: 



3(x+2)=2(x-10)

We move all terms to the left:

3(x+2)-(2(x-10))=0

We multiply parentheses

3x-(2(x-10))+6=0



We calculate terms in parentheses: -(2(x-10)), so:

2(x-10)

We multiply parentheses

2x-20

Back to the equation:

-(2x-20)



We get rid of parentheses

3x-2x+20+6=0

We add all the numbers together, and all the variables

x+26=0

We move all terms containing x to the left, all other terms to the right

x=-26

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