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4(7+5x^2)=348
We move all terms to the left:
4(7+5x^2)-(348)=0
We multiply parentheses
20x^2+28-348=0
We add all the numbers together, and all the variables
20x^2-320=0
a = 20; b = 0; c = -320;
Δ = b2-4ac
Δ = 02-4·20·(-320)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25600}=160$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*20}=\frac{-160}{40} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*20}=\frac{160}{40} =4 $
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