4(6x+3)=2(4x-2)

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Solution for 4(6x+3)=2(4x-2) equation: 



4(6x+3)=2(4x-2)

We move all terms to the left:

4(6x+3)-(2(4x-2))=0

We multiply parentheses

24x-(2(4x-2))+12=0



We calculate terms in parentheses: -(2(4x-2)), so:

2(4x-2)

We multiply parentheses

8x-4

Back to the equation:

-(8x-4)



We get rid of parentheses

24x-8x+4+12=0

We add all the numbers together, and all the variables

16x+16=0

We move all terms containing x to the left, all other terms to the right

16x=-16

x=-16/16

x=-1

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