5+4(b+3)=132

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Solution for 5+4(b+3)=132 equation: 



5+4(b+3)=132

We move all terms to the left:

5+4(b+3)-(132)=0

We add all the numbers together, and all the variables

4(b+3)-127=0

We multiply parentheses

4b+12-127=0

We add all the numbers together, and all the variables

4b-115=0

We move all terms containing b to the left, all other terms to the right

4b=115

b=115/4

b=28+3/4

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