4(6x+1)-5=3(4x+3)+38

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Solution for 4(6x+1)-5=3(4x+3)+38 equation: 



4(6x+1)-5=3(4x+3)+38

We move all terms to the left:

4(6x+1)-5-(3(4x+3)+38)=0

We multiply parentheses

24x-(3(4x+3)+38)+4-5=0



We calculate terms in parentheses: -(3(4x+3)+38), so:

3(4x+3)+38

We multiply parentheses

12x+9+38

We add all the numbers together, and all the variables

12x+47

Back to the equation:

-(12x+47)



We add all the numbers together, and all the variables

24x-(12x+47)-1=0

We get rid of parentheses

24x-12x-47-1=0

We add all the numbers together, and all the variables

12x-48=0

We move all terms containing x to the left, all other terms to the right

12x=48

x=48/12

x=4

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