4(6x+1)=3(4x+3)=38

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Solution for 4(6x+1)=3(4x+3)=38 equation:



4(6x+1)=3(4x+3)=38
We move all terms to the left:
4(6x+1)-(3(4x+3))=0
We multiply parentheses
24x-(3(4x+3))+4=0
We calculate terms in parentheses: -(3(4x+3)), so:
3(4x+3)
We multiply parentheses
12x+9
Back to the equation:
-(12x+9)
We get rid of parentheses
24x-12x-9+4=0
We add all the numbers together, and all the variables
12x-5=0
We move all terms containing x to the left, all other terms to the right
12x=5
x=5/12
x=5/12

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