4(6+4k)=12(k+5)

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Solution for 4(6+4k)=12(k+5) equation: 



4(6+4k)=12(k+5)

We move all terms to the left:

4(6+4k)-(12(k+5))=0

We add all the numbers together, and all the variables

4(4k+6)-(12(k+5))=0

We multiply parentheses

16k-(12(k+5))+24=0



We calculate terms in parentheses: -(12(k+5)), so:

12(k+5)

We multiply parentheses

12k+60

Back to the equation:

-(12k+60)



We get rid of parentheses

16k-12k-60+24=0

We add all the numbers together, and all the variables

4k-36=0

We move all terms containing k to the left, all other terms to the right

4k=36

k=36/4

k=9

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