4(5x-7)=10x2

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Solution for 4(5x-7)=10x2 equation: 



4(5x-7)=10x^2

We move all terms to the left:

4(5x-7)-(10x^2)=0

determiningTheFunctionDomain
-10x^2+4(5x-7)=0

We multiply parentheses

-10x^2+20x-28=0

a = -10; b = 20; c = -28;
Δ = b2-4ac
Δ = 202-4·(-10)·(-28)
Δ = -720
Delta is less than zero, so there is no solution for the equation

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