4(n-2)-(3-6n)=9n

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Solution for 4(n-2)-(3-6n)=9n equation: 



4(n-2)-(3-6n)=9n

We move all terms to the left:

4(n-2)-(3-6n)-(9n)=0

We add all the numbers together, and all the variables

4(n-2)-(-6n+3)-9n=0

We add all the numbers together, and all the variables

-9n+4(n-2)-(-6n+3)=0

We multiply parentheses

-9n+4n-(-6n+3)-8=0

We get rid of parentheses

-9n+4n+6n-3-8=0

We add all the numbers together, and all the variables

n-11=0

We move all terms containing n to the left, all other terms to the right

n=11

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