4(5x+3)=21x+15

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Solution for 4(5x+3)=21x+15 equation: 



4(5x+3)=21x+15

We move all terms to the left:

4(5x+3)-(21x+15)=0

We multiply parentheses

20x-(21x+15)+12=0

We get rid of parentheses

20x-21x-15+12=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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