45(x-1)-40(3x+1)=12(x+1)1

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Solution for 45(x-1)-40(3x+1)=12(x+1)1 equation: 



45(x-1)-40(3x+1)=12(x+1)1

We move all terms to the left:

45(x-1)-40(3x+1)-(12(x+1)1)=0

We multiply parentheses

45x-120x-(12(x+1)1)-45-40=0



We calculate terms in parentheses: -(12(x+1)1), so:

12(x+1)1

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)



We add all the numbers together, and all the variables

-75x-(12x+12)-85=0

We get rid of parentheses

-75x-12x-12-85=0

We add all the numbers together, and all the variables

-87x-97=0

We move all terms containing x to the left, all other terms to the right

-87x=97

x=97/-87

x=-1+10/87

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