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4(5w+3)=6(w+2)
We move all terms to the left:
4(5w+3)-(6(w+2))=0
We multiply parentheses
20w-(6(w+2))+12=0
We calculate terms in parentheses: -(6(w+2)), so:We get rid of parentheses
6(w+2)
We multiply parentheses
6w+12
Back to the equation:
-(6w+12)
20w-6w-12+12=0
We add all the numbers together, and all the variables
14w=0
w=0/14
w=0
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