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4(5+3x)=7x+-2(3-4x)
We move all terms to the left:
4(5+3x)-(7x+-2(3-4x))=0
We add all the numbers together, and all the variables
4(3x+5)-(7x+-2(-4x+3))=0
We use the square of the difference formula
4(3x+5)-(7x-2(-4x+3))=0
We multiply parentheses
12x-(7x-2(-4x+3))+20=0
We calculate terms in parentheses: -(7x-2(-4x+3)), so:We get rid of parentheses
7x-2(-4x+3)
We multiply parentheses
7x+8x-6
We add all the numbers together, and all the variables
15x-6
Back to the equation:
-(15x-6)
12x-15x+6+20=0
We add all the numbers together, and all the variables
-3x+26=0
We move all terms containing x to the left, all other terms to the right
-3x=-26
x=-26/-3
x=8+2/3
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