(Y-p)(p-1)=p

Solution for (Y-p)(p-1)=p equation:

(-Y)(Y-1)=Y

We move all terms to the left:

(-Y)(Y-1)-(Y)=0

We add all the numbers together, and all the variables

(-1Y)(Y-1)-Y=0

We add all the numbers together, and all the variables

-1Y+(-1Y)(Y-1)=0

We multiply parentheses ..

(-1Y^2+Y)-1Y=0

We get rid of parentheses

-1Y^2+Y-1Y=0

We add all the numbers together, and all the variables

-1Y^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{0}{-2}=0$