4(4x-7)-3=4(x-2)

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Solution for 4(4x-7)-3=4(x-2) equation: 



4(4x-7)-3=4(x-2)

We move all terms to the left:

4(4x-7)-3-(4(x-2))=0

We multiply parentheses

16x-(4(x-2))-28-3=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

16x-(4x-8)-31=0

We get rid of parentheses

16x-4x+8-31=0

We add all the numbers together, and all the variables

12x-23=0

We move all terms containing x to the left, all other terms to the right

12x=23

x=23/12

x=1+11/12

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