1/2(d-7)-7/3(2d-4)=7/6

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Solution for 1/2(d-7)-7/3(2d-4)=7/6 equation: 



1/2(d-7)-7/3(2d-4)=7/6

We move all terms to the left:

1/2(d-7)-7/3(2d-4)-(7/6)=0



Domain of the equation: 2(d-7)!=0

d∈R





Domain of the equation: 3(2d-4)!=0

d∈R



We add all the numbers together, and all the variables

1/2(d-7)-7/3(2d-4)-(+7/6)=0

We get rid of parentheses

1/2(d-7)-7/3(2d-4)-7/6=0

We calculate fractions


(18d2/(2(d-7)*3(2d-4)*6)+(-84dd/(2(d-7)*3(2d-4)*6)+(-42d^2d/(2(d-7)*3(2d-4)*6)=0



We calculate terms in parentheses: +(18d2/(2(d-7)*3(2d-4)*6)+(-84dd/(2(d-7)*3(2d-4)*6)+(-42d^2d/(2(d-7)*3(2d-4)*6), so:

18d2/(2(d-7)*3(2d-4)*6)+(-84dd/(2(d-7)*3(2d-4)*6)+(-42d^2d/(2(d-7)*3(2d-4)*6

We can not solve this equation

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