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4(4x-4)=5(3x+3)
We move all terms to the left:
4(4x-4)-(5(3x+3))=0
We multiply parentheses
16x-(5(3x+3))-16=0
We calculate terms in parentheses: -(5(3x+3)), so:We get rid of parentheses
5(3x+3)
We multiply parentheses
15x+15
Back to the equation:
-(15x+15)
16x-15x-15-16=0
We add all the numbers together, and all the variables
x-31=0
We move all terms containing x to the left, all other terms to the right
x=31
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