4(4x-2)=7+x

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Solution for 4(4x-2)=7+x equation: 



4(4x-2)=7+x

We move all terms to the left:

4(4x-2)-(7+x)=0

We add all the numbers together, and all the variables

4(4x-2)-(x+7)=0

We multiply parentheses

16x-(x+7)-8=0

We get rid of parentheses

16x-x-7-8=0

We add all the numbers together, and all the variables

15x-15=0

We move all terms containing x to the left, all other terms to the right

15x=15

x=15/15

x=1

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