7(x-3)=2(2x-2)

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Solution for 7(x-3)=2(2x-2) equation: 



7(x-3)=2(2x-2)

We move all terms to the left:

7(x-3)-(2(2x-2))=0

We multiply parentheses

7x-(2(2x-2))-21=0



We calculate terms in parentheses: -(2(2x-2)), so:

2(2x-2)

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

7x-4x+4-21=0

We add all the numbers together, and all the variables

3x-17=0

We move all terms containing x to the left, all other terms to the right

3x=17

x=17/3

x=5+2/3

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