4(4x-10)+10x=4(2x-3)+2(x-4)

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Solution for 4(4x-10)+10x=4(2x-3)+2(x-4) equation: 



4(4x-10)+10x=4(2x-3)+2(x-4)

We move all terms to the left:

4(4x-10)+10x-(4(2x-3)+2(x-4))=0

We add all the numbers together, and all the variables

10x+4(4x-10)-(4(2x-3)+2(x-4))=0

We multiply parentheses

10x+16x-(4(2x-3)+2(x-4))-40=0



We calculate terms in parentheses: -(4(2x-3)+2(x-4)), so:

4(2x-3)+2(x-4)

We multiply parentheses

8x+2x-12-8

We add all the numbers together, and all the variables

10x-20

Back to the equation:

-(10x-20)



We add all the numbers together, and all the variables

26x-(10x-20)-40=0

We get rid of parentheses

26x-10x+20-40=0

We add all the numbers together, and all the variables

16x-20=0

We move all terms containing x to the left, all other terms to the right

16x=20

x=20/16

x=1+1/4

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