(3x-8)x=336

Solution for (3x-8)x=336 equation:

(3x-8)x=336

We move all terms to the left:

(3x-8)x-(336)=0

We multiply parentheses

3x^2-8x-336=0

a = 3; b = -8; c = -336;
Δ = b2-4ac
Δ = -82-4·3·(-336)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-64}{2*3}=\frac{-56}{6}
=-9+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+64}{2*3}=\frac{72}{6}
=12
$