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4(4x+5)=6(3x-1/3)
We move all terms to the left:
4(4x+5)-(6(3x-1/3))=0
We add all the numbers together, and all the variables
4(4x+5)-(6(+3x-1/3))=0
We multiply parentheses
16x-(6(+3x-1/3))+20=0
We multiply all the terms by the denominator
16x*3))-(6(+3x-1+20*3))=0
We add all the numbers together, and all the variables
16x*3))-(6(3x+59))=0
We add all the numbers together, and all the variables
16x*3))-(6(3x=0
Wy multiply elements
48x^2=0
a = 48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·48·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{96}=0$
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