4(4x+3)=19x+9

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Solution for 4(4x+3)=19x+9 equation: 



4(4x+3)=19x+9

We move all terms to the left:

4(4x+3)-(19x+9)=0

We multiply parentheses

16x-(19x+9)+12=0

We get rid of parentheses

16x-19x-9+12=0

We add all the numbers together, and all the variables

-3x+3=0

We move all terms containing x to the left, all other terms to the right

-3x=-3

x=-3/-3

x=1

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