4(4x+1)=3x-4(6/x)+8

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Solution for 4(4x+1)=3x-4(6/x)+8 equation:



4(4x+1)=3x-4(6/x)+8
We move all terms to the left:
4(4x+1)-(3x-4(6/x)+8)=0
Domain of the equation: x)+8)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
4(4x+1)-(3x-4(+6/x)+8)=0
We multiply parentheses
16x-(3x-4(+6/x)+8)+4=0
We multiply all the terms by the denominator
16x*x)+8)-(3x-4(+4*x)+8)+6=0
We add all the numbers together, and all the variables
16x*x)+8)-(3x-4(+4x)+8)+6=0
Wy multiply elements
16x^2+4x)+8)+6=0

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